Question

What are the x- intercepts of the function f(x)= -2x-3+20?

Answer 1

x = .464

Explanation:

Assumptions: Equation is
`-2x^3+20`. Thus having an asymptote at the value x=0.

• To solve for the x-intercepts, we plug in 0 for f(x).
• We can subtract 20 from both sides, leaving us with
  `-20 = -2x^-3.`
• We can divide both sides by -2.
  `10=1/x^3`.
• Now we multiply both sides by x^3, to get rid of the denominator on the right-hand side.
  `10x^3=1`.
• We now divide both sides by 10 and take the cube root. Leaving us with x =
  `\sqrt[3]{1/10}` or .464. (One x-intercept.)