Answer:
![a=(v^2)/(r)](https://img.qammunity.org/2022/formulas/physics/high-school/dfcts1pvybeq88uknchtfuenc6bjb7o4rj.png)
![v=√(a*r)](https://img.qammunity.org/2022/formulas/physics/high-school/4we4u5ndw44jq5qx68fdhlesuzqut99hso.png)
![r=(v^2)/(a)](https://img.qammunity.org/2022/formulas/physics/high-school/4ri6jf8zqw5w9osyqe5u73r3g9ddoyoctt.png)
Step-by-step explanation:
This is the formula for centripetal acceleration in terms of the tangential velocity (v) and the radius of the circular motion (r). The expression for the acceleration is already given, so simply type it as shown:
![a=(v^2)/(r)](https://img.qammunity.org/2022/formulas/physics/high-school/dfcts1pvybeq88uknchtfuenc6bjb7o4rj.png)
For the velocity (v) multiply by "r" both sides and then use the square root to solve for v:
![a*r=v^2\\v=√(a*r)](https://img.qammunity.org/2022/formulas/physics/high-school/4tfe32iihxkvowil22edzaob327rkus3ce.png)
For the radius multiply both sides by r and then divide both sides by the acceleration (a) in order to isolate r completely:
![a*r=v^2\\r=(v^2)/(a)](https://img.qammunity.org/2022/formulas/physics/high-school/d2yggvrvq1w4keg7v7ihuywq1iby1nqiac.png)