Question

The total current of a parallel circuit is 9+j2 amps and the current of one component of the circuit is 3−j5 amps. What is the current of the other component of the circuit?

Answer 1

Apply law of total resistance in parallel circuit

`\\ \tt\hookrightarrow (1)/(R)=(1)/(R_1)+(1)/(R_2)`

`\\ \tt\hookrightarrow (1)/(9+2J)=(1)/(3-5j)+(1)/(R_2)`

`\\ \tt\hookrightarrow (1)/(R_2)=(1)/(9+2J)-(1)/(3-5J)`

`\\ \tt\hookrightarrow (1)/(R_2)=(3-5J-9-2J)/((9+2J)(3-5J))`

`\\ \tt\hookrightarrow R_2=((9+2J)(3-5J))/(-6-7J)`