Question

How many grams of KCl are produced if 25g of KCIO3 decompose?

2KCIO3
2KCI
+
302

Answer 1

15 g

Step-by-step explanation:

The reaction that takes place is:

• 2KCIO₃ → 2KCI + 3O₂

First we convert 25 g of KCIO₃ to moles, using its molar mass:

• 25 g ÷ 122.55 g/mol = 0.204 mol KCIO₃

Then we convert KCIO₃ moles to KCl moles, using the stoichiometric coefficients:

• 0.204 mol KCIO₃ *
  `(2molKCl)/(2molKClO_3)` = 0.204 mol KCl

Finally we convert KCl moles to grams, using the molar mass of KCl:

• 0.204 mol KCl * 74.55 g/mol = 15.2 g