Question

Writing Sample: At what pressure would 0.150 mole of nitrogen gas at -23.0 o C occupy 8.90 L?

Answer 1

`P=0.346atm`

Step-by-step explanation:

Hello!

In this case, since the ideal gas equation is:

`PV=nRT`

And we are asked to compute the pressure, we obtain:

`P=(nRT)/(V)`

Thus, since the temperature must be expressed in Kelvins, we plug in to obtain:

`P=(0.150mol*0.08206(atm*L)/(mol*K)*250.15K)/(8.90L)\\\\P=0.346atm`

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