Question

Sum of 2 numbers is 42, and their difference is 8. What are the numbers?​

Answer 1

`let \: the \: numbers \: be \: x \: and \: y \\ x + y = 42....(1) \\ x - y = 8....(2) \\ now \\ x + y = 42 \\ x = 42 - y \\ again \\ x - y = 8 \\ x = 8 + y \\ putting \: the \: value \: of(x) \\ \\ 42 - y = 8 + y \\ 2y = 42 - 8 \\ 2y = 34 \\ y = 34 / 2 \\ y = 17 \\ putting \: the \: value \: in \: equation \: (1) \\ x + y = 42 \\ x = 42 - 17 \\ x = 25`

x=25 and y=17

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Answer 2

25 , 17

Explanation:

Let the unknown two numbers be x & y.

According to the question,

Sum of 2 numbers is 42.

x + y = 42 ⇒ ( 1 )

Their difference is 8.

x - y = 8 ⇒ ( 2 )

First let us find the value of x.

( 1 ) + ( 2 )

x + y + x - y = 42 + 8

2x = 50

Divide both sides by 2.

x = 25

And now let us find the value of y.

x + y = 42

25 + y = 42

y = 42 - 25

y = 17

Therefore, the two numbers are 25 , 17

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