I need help ASAP. Thank you. Special right triangle.

Question

asked Oct 28, 2022 96.4k views

1 Answer

Guapo · Answer 1 · 2022-11-04T03:55:02+0000

Answer:

JK = 3
√(3)

Explanation:

Using the cosine ratio in the right triangle and the exact value

cos60° =
(1)/(2) , then

cos60° =
(adjacent)/(hypotenuse) =
(JK)/(JL) =
(JK)/(6√(3) ) =
(1)/(2) ( cross- multiply )

2JK = 6
√(3) ( divide both sides by 2 )

JK = 3
√(3)