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I need help ASAP. Thank you. Special right triangle.
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I need help ASAP. Thank you. Special right triangle.

I need help ASAP. Thank you. Special right triangle.-example-1
User Christos Baziotis
by
3.5k points

1 Answer

9 votes

Answer:

JK = 3
√(3)

Explanation:

Using the cosine ratio in the right triangle and the exact value

cos60° =
(1)/(2) , then

cos60° =
(adjacent)/(hypotenuse) =
(JK)/(JL) =
(JK)/(6√(3) ) =
(1)/(2) ( cross- multiply )

2JK = 6
√(3) ( divide both sides by 2 )

JK = 3
√(3)

User Guapo
by
3.4k points
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