Question

How many gallons of a 60% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 50% antifreeze

Answer 1

120 gallons

Explanation:

You want the number of gallons of 60% antifreeze to mix with 60 gallons of 30% antifreeze to make a mixture that is 50% antifreeze.

Setup

Let x represent the number of gallons of 60% antifreeze in the mix. Then the amount of antifreeze in the mix is ...

0.60x +0.30(60) = 0.50(x +60)

Solution

Simplifying gives ...

0.60x +18 = 0.50x +30

0.10x = 12 . . . . . . . . . . . . . . subtract 18+0.50x

x = 120 . . . . . . . . . . . . multiply by 10

120 gallons of 60% antifreeze must be mixed into the solution.

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