Answer:
120 gallons
Explanation:
You want the number of gallons of 60% antifreeze to mix with 60 gallons of 30% antifreeze to make a mixture that is 50% antifreeze.
Setup
Let x represent the number of gallons of 60% antifreeze in the mix. Then the amount of antifreeze in the mix is ...
0.60x +0.30(60) = 0.50(x +60)
Solution
Simplifying gives ...
0.60x +18 = 0.50x +30
0.10x = 12 . . . . . . . . . . . . . . subtract 18+0.50x
x = 120 . . . . . . . . . . . . multiply by 10
120 gallons of 60% antifreeze must be mixed into the solution.
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