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1 vote
The diagram below illustrates a 10.0kg mass held at rest on a frictionless, 30 incline by force F. What is the approximate magnitude of force F?

User Rob Mason
by
7.9k points

2 Answers

5 votes

Answer:

49.0 N

Step-by-step explanation:

Draw a free body diagram of the mass. There are 3 forces:

Weight force mg pulling down,

Normal force N pushing perpendicular to the incline,

and applied force F pushing parallel to the incline.

Sum of forces in the parallel direction:

∑F = ma

F − mg sin θ = 0

F = mg sin θ

F = (10.0 kg) (9.8 m/s²) sin 30°

F = 49.0 N

User Picus
by
7.8k points
7 votes

98N times sin(30), or 49 N.

User Omar Tammam
by
8.3k points