Final answer:
The question discusses calculating the percentages of milk and water in a mixture using the rule of alligation. The scenario includes mixing defined amounts of pure milk and pure water into a third container. The ratio obtained from the alligation rule represents the relative concentrations of milk to water in the new mixture.
Step-by-step explanation:
The student's question deals with the concept of mixing solutions of different concentrations and finding the resulting percentages of each component in the new mixture using the rule of alligation. The given scenario describes two bottles: one containing only milk (bottle A) and another containing only water (bottle B). The question involves transferring a portion of the contents from these two bottles into a third bottle (bottle C) and determining the percentages of milk (m%) and water (n%) in this mixture.
When we mix 2/3 of bottle A (which contains pure milk) with 1/3 of bottle B (which contains pure water), we get a mixture in bottle C that contains a certain percentage of milk and water. Applying the rule of alligation, we get a ratio that represents the concentration of milk to the concentration of water in bottle C.
To calculate the percentage of milk and water in bottle C, one could apply the multiplying factors to the volumes of each liquid. Since milk is the reference, we would compare the concentration of milk in bottle C with the concentration of water (which is implicitly zero since bottle B contains only water).
Using volume as a capacity measure is essential here, as a liter is the standard unit for larger volumes of liquid, similar to how the capacity of a jug of milk or a baby bottle is measured. Indeed, volume is best represented in liters when dealing with such quantities, which may vary from a few milliliters (mL) for smaller containers to liters (L) for larger volumes.