To find an equation of a line that is parallel to y = 3x - 2 and passes through the point (2, 9), you can use the fact that parallel lines have the same slope.
The slope of the line y = 3x - 2 is 3. So, the equation of the line parallel to it is:
y = 3x + b
Now, we can use the point (2, 9) to find the value of b:
9 = 3(2) + b
9 = 6 + b
To solve for b, subtract 6 from both sides:
b = 9 - 6
b = 3
So, the equation of the line parallel to y = 3x - 2 and passing through (2, 9) is:
y = 3x + 3