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5 votes
Initial value for y=25.00^x

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5 votes

Answer:

25.00 for x = 0

Explanation:

We aren't told the range of x, nor of any "initial value" of x. If we assume this is the start of a sequence and that x is the number of that sequence, we can say that the initial value of x is zero (0). We can then say that:

y = 25.00^x becomes y = 25.00^0

Any number raised to the zeroth power is 1.

The initial value would be 25.00 for a sequence of x starting at x=0.

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