Question

If the lines x-3y=10 and kx+6y-1=0 are parallel, then the value of 'k' is what ​

Answer 1

x - 3y = 10

-3y = -x + 10

y = (1/3)x - (10/3)

kx + 6y = 1

6y = -kx + 1

y = (-k/6)x + (1/6)

k = -2