Question

a sample of oxygen collected over water at a temperature of 35.0∘c exerts a pressure of 450. torr. what is the dry gas pressure of the oxygen? (the vapor pressure of water at 35.0∘c is 42.2 torr.)

Answer 1

This site tells me that vapour pressure of water at

35.0

∘

C

=

42.2

⋅

m

m

⋅

H

g

.

Step-by-step explanation:

P

collected

=

P

gas

+

P

SVP

,

P

SVP

is given above, and is called the saturated vapour pressure. This should have been quoted with the question.

Thus

P

gas

≅

700

⋅

m

m

⋅

H

g

.