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What is the molarity of a solution containing 2.8 moles of LiCl and a volume of 5.00 × 102 mL?

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Final answer:

The molarity of a solution containing 2.8 moles of LiCl in a volume of 500 mL is 5.6 M.

Step-by-step explanation:

The molarity of a solution is defined as the number of moles of solute per liter of solution. To find the molarity, you use the formula:

Molarity (M) = moles of solute / volume of solution in liters

For the given problem, you have 2.8 moles of LiCl and a volume of 5.00 × 10² mL of solution. Since molarity is expressed per liter, you need to convert the volume from milliliters to liters by dividing by 1000. This gives a volume of 0.500 liters.

Now, you can calculate the molarity:

Molarity (M) = 2.8 moles / 0.500 liters = 5.6 M

Therefore, the molarity of the LiCl solution is 5.6 M.

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