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Answer: 1,88×10²³ atoms of Br in 25g of Br
Step-by-step explanation:
25g Br
1 mol of Br =79,9g Br
Number of Avogadro: 6,022×10²³ = 1 mol
25gBr× 1molBr/79,9gBr =
6,022×10²³ atoms of Br/1 mol Br =
1,88×10²³ atoms of Bromine
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