Final answer:
The original pure line peppers were probably AABB (red phenotype) and aabb (colorless phenotype). They were crossed to produce all AaBb (red phenotype) in the F1, which when intercrossed produce the F2 generation with red, yellow, and colorless phenotypes in roughly 9:3:4 ratio.
Step-by-step explanation:
This problem is related to Mendelian genetics and the interpretation of Punnett squares for dihybrid crosses. In brief, it seems that the trait for color in these pepper plants is governed by two genes, with three possible colors arising: red, colorless (white) and yellow. Given the F2 results, we're likely dealing with a crossing of two dihybrid heterozygotes (AaBb x AaBb).
Here's why: gene A is responsible for the transformation from colorless to yellow. If in lower case (aa), it will represent the colorless (white) phenotype. Gene B is responsible for the transformation from yellow to red. If in lower case (bb), it will represent the yellow phenotype. The dominant alleles (AA, BB) in concert, transform colorless to yellow, then yellow to red.
So, to get the ratios of red, yellow, and colorless peppers roughly in 9:3:4 (akin to Mendelian dihybrid cross ratios), the original pure line peppers were probably AABB (red phenotype) crossed with aabb (colorless phenotype). The resulting F1 generation would all be AaBb (red phenotype) due to dominance, which when intercrossed produce the F2 with red, yellow, and colorless phenotypes in the observed ratio.
Learn more about Mendelian genetics