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Determine the exact value of one of the zeros g(x) = 12x^4 − 20x^3 − 45x^2 + 80x − 12

Determine the exact value of one of the zeros g(x) = 12x^4 − 20x^3 − 45x^2 + 80x − 12
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4 votes
Determine the exact value of one of the zeros g(x) = 12x^4 − 20x^3 − 45x^2 + 80x − 12

User Joel Holmes
by
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1 Answer

4 votes

Answer:

Hi,

Explanation:


\begin{array}ccccc&x^4&x^3&x^2&x&1\\---&---&---&---&---&---\\&12&-20&-45&80&12\\x=2&&24&8&-74&12\\&12&4&-37&6&0\\x=-2&&-24&40&-6&\\&12&-20&3&0&\\x=(3)/(2) &&18&-3&&\\&12&-2&0&&\\x=(1)/(6) &&2\\&12&0&&&\\---&---&---&---&---&---\\\end {array}\\\\\\\\\boxed{g(x)=(x+2)(x-2)(2x-3)(6x-1)}

User Ecantu
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