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Find all real zeros of the function. h(x)=5x(x-1)^(2)(x-3)^(2)

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x = {0; 1; 3}

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To find the real zeros of the function h(x) = 5x(x-1)²(x-3)², we need to solve for x when h(x) is equal to zero.

Setting each factor equal to zero, we have:

  1. x = 0
  2. (x - 1)² = 0 ⇒ x - 1 = 0 ⇒ x = 1
  3. (x - 3)² = 0 ⇒ x - 3 = 0 ⇒ x = 3

Solving these equations, we find the real zeros of the function are:

  • x = 0
  • x = 1
  • x = 3

User Zhuzhumouse
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