x = {0; 1; 3}
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To find the real zeros of the function h(x) = 5x(x-1)²(x-3)², we need to solve for x when h(x) is equal to zero.
Setting each factor equal to zero, we have:
- x = 0
- (x - 1)² = 0 ⇒ x - 1 = 0 ⇒ x = 1
- (x - 3)² = 0 ⇒ x - 3 = 0 ⇒ x = 3
Solving these equations, we find the real zeros of the function are: