Question

What is the perimeter of a rectangle with an area of 2x^2+11x+5 in^2?​

Answer 1

6x + 14

Explanation:

Area = side x side

Factor the quadratic:

2x^2 +10x / +1x +5

2x(x+5) 1 (x+5)

(2x + 1) (x+5)

^These are your two sides

Perimeter =2L + 2W

(2(2x+1)) + (2(x+5))

4x+4+2x+10 = final answer 6x + 14