Answer:
4 meters in width and 9 meters in length.
Explanation:
Let's denote the width of the rectangular room as "W" meters. According to the problem, the room is 5 meters longer than it is wide, so the length can be represented as "W + 5" meters.
The perimeter of a rectangle is calculated using the formula:
Perimeter = 2 × (Length + Width)
In this case, the perimeter is given as 26 meters, so we can set up the equation:
26 = 2 × (W + (W + 5))
Now, let's simplify the equation:
26 = 2 × (2W + 5)
Divide both sides by 2:
13 = 2W + 5
Subtract 5 from both sides:
13 - 5 = 2W
8 = 2W
Now, divide by 2 to solve for W:
W = 8 / 2
W = 4
So, the width of the room is 4 meters, and the length is 5 meters longer:
Length = W + 5
Length = 4 + 5
Length = 9
Therefore, the dimensions of the room are 4 meters in width and 9 meters in length.