Question

In standard (x,y) coordinate plane, what is the distance between the points (-4,2) and (1,-10)?

Answer 1

Answer: 13 units

Explanation:

We can use the distance formula to solve this question.

Given:

`\displaystyle d=\sqrt{(x_(2)-x_(1))^2 +(y_(2)-y_(1))^2}`

Substitute given coordinate points:

`\displaystyle d=√((1--4)^2 +(-10-2)^2)`

Subtract:

`\displaystyle d=√((5)^2 +(-12)^2)`

Square:

`\displaystyle d=√(25 +144)`

Add:

`\displaystyle d=√(169)`

Square root of 169:

`\displaystyle d=13`