Question

Find the equation of the line perpendicular to y = -1/2x - 5 that passes through the point (2, 7). Write this line in slope-intercept form.

Answer 1

y = 2x + 3

Explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

given the equation of the line

y = -
`(1)/(2)` x - 5 ← in slope- intercept form

with slope m = -
`(1)/(2)`

given a line with slope m then the slope of a line perpendicular to it is

`m_(perpendicular)` = -
`(1)/(m)` = -
`(1)/(-(1)/(2) )` = 2 , then

y = 2x + c ← is the partial equation

to find c , substitute the point (2, 7 ) into the partial equation

7 = 2(2) + c = 4 + c ( subtract 4 from both sides )

3 = c

y = 2x + 3 ← equation of perpendicular line