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Find the product of (–d + e)(4e + d)

User Starhusker
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Answer:

Product = 4e^2 - d^2 - 3ed

Explanation:

  • (-d + e) and (4e + d) are both binomials.

Since we're trying to find the product of two binomials, we can use the FOIL method, where:

  • F refers to the product of the first two terms (-d and 4e),
  • O refers to the product of the outer two terms (-d and d),
  • I refers to the product of the inner two terms (e and 4e),
  • and L refers to the product of the last two terms (e and d).

Thus, we find all the products and simplify:

(-d * 4e) + (-d * d) + (e * 4e) + (e * d)

-4ed - d^2 + 4e^2 + ed

4e^2 - d^2 + (-4ed + ed)

4e^2 - d^2 - 3ed

Thus, the product of (-d + e)(4e + d) is 4e^2 - d^2 - 3ed.

User Sheepwalker
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