Question

Calculate the kinetic energy acquired by a 7.2-g nail when it is

struck by a 850-g hammer moving with an initial speed of 9.0
m/sm/s.

Answer 1

The kinetic energy acquired by the nail when struck by the hammer is 0.32832 Joules.

Step-by-step explanation:

To calculate the kinetic energy acquired by the nail when struck by the hammer, we need to use the formula for kinetic energy: KE = (1/2)mv^2.

First, we need to convert the mass of the nail from grams to kilograms. There are 1000 grams in 1 kilogram, so the mass of the nail is 7.2 g / 1000 = 0.0072 kg.

Next, we need to calculate the velocity of the hammer. The initial speed is given as 9.0 m/s.

Now we can plug in the values into the formula:

KE = (1/2)(0.0072 kg)(9.0 m/s)^2

Simplifying the equation:

KE = (1/2)(0.0072 kg)(81 m^2/s^2)

KE = 0.32832 Joules

Therefore, the kinetic energy acquired by the nail when struck by the hammer is 0.32832 Joules.

Note: It's important to remember that the kinetic energy is a scalar quantity and is always positive.

Answer 2

the kinetic energy acquired by the 7.2-g nail when struck by the 850-g hammer moving with an initial speed of 9.0 m/s is approximately 0.2916 Joules.

Step-by-step explanation:

To calculate the kinetic energy acquired by the nail, we need to use the formula:

Kinetic energy = 0.5 * mass * velocity^2

First, let's convert the mass of the nail and hammer from grams to kilograms:

Mass of nail = 7.2 g = 0.0072 kg

Mass of hammer = 850 g = 0.85 kg

Now we can calculate the kinetic energy acquired by the nail:

Kinetic energy = 0.5 * (mass of nail) * (velocity of hammer)^2

= 0.5 * 0.0072 kg * (9.0 m/s)^2

= 0.5 * 0.0072 kg * 81 m^2/s^2

= 0.2916 kg * m^2/s^2

= 0.2916 Joules

Therefore, the kinetic energy acquired by the 7.2-g nail when struck by the 850-g hammer moving with an initial speed of 9.0 m/s is approximately 0.2916 Joules.