89.4k views
1 vote
appose a capacitor has an opposite net charge of magnitude 8.31 C on its plates. If an electric field of magnitude 2.45 kV mm is needed etween the plates, calculate the area of the plate (in in"). nter your answer to within two decimal points Ilse a poriad (full

User Pidizzle
by
8.5k points

1 Answer

3 votes
To calculate the area of the plate, we can use the formula for the electric field between the plates of a capacitor:

E = V/d,

where E is the electric field, V is the voltage, and d is the distance between the plates.

Given that the electric field is 2.45 kV mm or 2.45 x 10^6 V/m, we need to convert it to volts per meter. 1 mm is equal to 0.001 meters, so the electric field becomes 2.45 x 10^6 V/0.001 m = 2.45 x 10^9 V/m.

The voltage across the plates can be calculated using the formula:

V = Q/C,

where Q is the net charge and C is the capacitance.

Given that the net charge is 8.31 C, we need to find the capacitance to calculate the voltage. Without the value of the capacitance, we cannot proceed with the calculation of the area. Could you please provide the capacitance value?
User Haim Lvov
by
8.6k points