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Find the value of x to the nearest tenth . The image is below .

Find the value of x to the nearest tenth . The image is below .-example-1

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3 votes

Answer :

  • 2.8

Step-by-step explanation :

Let us consider two triangles,
\sf\triangle ABC and
\sf \triangle BDC,

In
\sf\triangle ABC,

Using pythagoras theorm,


\sf (H)^2= (B)^2 + (P)^2

  • H is Hypotenuse
  • B is base
  • P is perpendicular


\sf (AC)^2 = (BC)^2 + (AB)


\sf (9)^2 (BC)^2 +(8)^2


\sf 81 = (BC)^2 + 64


\sf (BC)^2 = 81-64


\sf (BC)^2= 17


\sf BC = \sqrt 17

In
\sf \triangle BDC,

Using pythagoras theorm,


\sf (H)^2= (B)^2 + (P)^2


\sf (BC)^2= (BD)^2 + (CD)^2


\sf (\sqrt 17 )^2 =(x)^2 + (3)^2


\sf 17 = x^2 + 9


\sf 17-9= x^2


\sf 8 = x^2


\sf x = \sqrt 8


\sf x = 2.8

Find the value of x to the nearest tenth . The image is below .-example-1
User Dhg
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