Answer:
B) ◻ (1,1,1,1,1,1,1,1,0)
Explanation:
Let's evaluate each option to see which one cannot be a value of ◻:
A) ◻(0,0,0,0,0,0,0,0,1)
Plugging in the values, we get:
◻(0,0,0,0,0,0,0,0,1) = (0)(0) - (0)(0) + (00)^2 · (00)^2 / 1
Since all the terms are zero, the result is 0.
B) ◻(1,1,1,1,1,1,1,1,0)
Plugging in the values, we get:
◻(1,1,1,1,1,1,1,1,0) = (1)(1) - (1)(1) + (11)^2 · (11)^2 / 0
Here, we encounter a division by zero, which is undefined.
C) ◻(2,2,2,2,2,2,2,2,10)
Plugging in the values, we get:
◻(2,2,2,2,2,2,2,2,10) = (2)(2) - (2)(2) + (22)^2 · (22)^2 / 10
Simplifying, we get:
◻(2,2,2,2,2,2,2,2,10) = 0
D) ◻(2,3,1,4,5,6,7,0,10)
Plugging in the values, we get:
◻(2,3,1,4,5,6,7,0,10) = (2)(3) - (1)(4) + (56)^2 · (70)^2 / 10
Simplifying, we get:
◻(2,3,1,4,5,6,7,0,10) = 6 - 4 + 1800 · 0 / 10
Since the term 1800 · 0 results in 0, the final result is 6 - 4 + 0 / 10 = 2.
From the above calculations, we see that option B) ◻(1,1,1,1,1,1,1,1,0) cannot be a value of ◻ as it involves division by zero, which is undefined.