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If ◻(a,b,c,d,e,f,g,h,i) = (a)(b) — (c)(d) + (ef)^2 (gh)^2 / i

Which cannot be a value of ◻?
A) ◻ (0,0,0,0,0,0,0,0,1)
B) ◻ (1,1,1,1,1,1,1,1,0)
C) ◻(2,2,2,2,2,2,2,2, 10)
D) ◻(2,3,1,4,5,6,7,0,10)

1 Answer

5 votes

Answer:

B) ◻ (1,1,1,1,1,1,1,1,0)

Explanation:

Let's evaluate each option to see which one cannot be a value of ◻:

A) ◻(0,0,0,0,0,0,0,0,1)

Plugging in the values, we get:

◻(0,0,0,0,0,0,0,0,1) = (0)(0) - (0)(0) + (00)^2 · (00)^2 / 1

Since all the terms are zero, the result is 0.

B) ◻(1,1,1,1,1,1,1,1,0)

Plugging in the values, we get:

◻(1,1,1,1,1,1,1,1,0) = (1)(1) - (1)(1) + (11)^2 · (11)^2 / 0

Here, we encounter a division by zero, which is undefined.

C) ◻(2,2,2,2,2,2,2,2,10)

Plugging in the values, we get:

◻(2,2,2,2,2,2,2,2,10) = (2)(2) - (2)(2) + (22)^2 · (22)^2 / 10

Simplifying, we get:

◻(2,2,2,2,2,2,2,2,10) = 0

D) ◻(2,3,1,4,5,6,7,0,10)

Plugging in the values, we get:

◻(2,3,1,4,5,6,7,0,10) = (2)(3) - (1)(4) + (56)^2 · (70)^2 / 10

Simplifying, we get:

◻(2,3,1,4,5,6,7,0,10) = 6 - 4 + 1800 · 0 / 10

Since the term 1800 · 0 results in 0, the final result is 6 - 4 + 0 / 10 = 2.

From the above calculations, we see that option B) ◻(1,1,1,1,1,1,1,1,0) cannot be a value of ◻ as it involves division by zero, which is undefined.

User Vladimir Protsenko
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