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ABC is a triangle.

CP = 3a
PA = 6a
MB = 2b
M is the midpoint of line AB and N is the midpoint of line CM.
Express NB in terms of c. Fully simplify your answer.

ABC is a triangle. CP = 3a PA = 6a MB = 2b M is the midpoint of line AB and N is the-example-1
User Tony Tarng
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1 Answer

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To find NB in terms of c, we can use the concept of midpoint theorem.

According to the midpoint theorem, in a triangle, if a line segment connects the midpoints of two sides of the triangle, then the length of that line segment is half the length of the third side.

Given that M is the midpoint of AB and N is the midpoint of CM, we can write:

AM = MB / 2

AN = NC / 2

Also, we know that CP = 3a and PA = 6a, so:

AC = AP + PC = 6a + 3a = 9a

Now, using the fact that AM + AN = AN, we have:

MB / 2 + NC / 2 = NB

Substitute the values of MB and NC:

2b / 2 + 9a / 2 = NB

Simplify:

b + 4.5a = NB

So, NB = b + 4.5a

Now, we need to express a in terms of c. Since CP = 3a, we can solve for a:

3a = c

a = c / 3

Now, substitute the value of a back into NB:

NB = b + 4.5(c / 3)

Simplify:

NB = b + 1.5c

So, NB in terms of c is given by NB = b + 1.5c.

User PolarisUser
by
8.0k points

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