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8x² + 18x + 0 = 0 using completing the square method​

1 Answer

6 votes

Answer:

x = 0

x = -3

Explanation:

T

Thereforeo solve the quadratic equation 8x² + 18x + 0 = 0 using the completing the square method, follow these steps:

Step 1: Divide the entire equation by the coefficient of x² to make the leading coefficient 1:

x² + (18/8)x + 0 = 0

x² + (9/4)x + 0 = 0

Step 2: Take half of the coefficient of x (which is 9/4) and square it:

(9/4) / 2 = 9/8

(9/8)² = 81/64

Step 3: Add and subtract the value from step 2 inside the parentheses:

x² + (9/4)x + 81/64 - 81/64 + 0 = 0

x² + (9/4)x + 81/64 - 81/64 = 0

Step 4: Factor the perfect square trinomial and simplify:

(x + 9/8)² - 81/64 = 0

Step 5: Solve for x by taking the square root of both sides:

(x + 9/8)² = 81/64

x + 9/8 = ±√(81/64)

Step 6: Solve for x:

x = -9/8 ± √(81/64)

x = -9/8 ± 9/8

This gives you two solutions:

x = 0

x = -3

Therefore, the solutions to the quadratic equation 8x² + 18x + 0 = 0 are x = 0 and x = -3.

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