Question

Help please VERY ARGENT

A man of mass 80 kg jump off the trolley of mass 160kg. If the initial speed of the man is 8m/s. At what initial speed will the trolley move​

Answer 1

HERE IS YOUR ANSWER

Step-by-step explanation:

To solve this problem, we can use the principle of conservation of momentum. According to this principle, the total momentum before the jump is equal to the total momentum after the jump.

Let's denote the initial speed of the trolley as Vt and the final speed of both the man and the trolley as Vf.

The momentum of an object is calculated by multiplying its mass by its velocity. Therefore, the initial momentum of the man is given by:

Initial momentum of the man = mass of the man * initial speed of the man

= 80 kg * 8 m/s

= 640 kg·m/s

The initial momentum of the trolley is given by:

Initial momentum of the trolley = mass of the trolley * initial speed of the trolley

= 160 kg * Vt

= 160Vt kg·m/s

According to the conservation of momentum, the total initial momentum is equal to the total final momentum. Therefore:

Initial momentum of the man + Initial momentum of the trolley = Final momentum of the man + Final momentum of the trolley

640 kg·m/s + 160Vt kg·m/s = 0 kg·m/s + (80 kg + 160 kg) * Vf

Simplifying the equation:

800Vt = 240Vf

Now, we can solve for the initial speed of the trolley (Vt) in terms of the final speed of both the man and the trolley (Vf):

Vt = (240/800) * Vf

Vt = 0.3 * Vf

Therefore, the initial speed of the trolley will be 0.3 times the final speed of both the man and the trolley.