Question

Two factory plants are making TV panels. Yesterday, Plant A produced 5000 fewer panels than Plant B did. Five percent of the panels from Plant A and 3% of the panels from Plant B were defective. How many panels did Plant B produce, if the two plants together produced 1190 defective panels?

Answer 1

Plant B produced 18000 panels.

Step-by-step explanation:

To find out how many panels Plant B produced, we need to determine the number of panels produced by Plant A. Let's call the number of panels produced by Plant B as 'x'.

According to the given information, Plant A produced 5000 fewer panels than Plant B. So, the number of panels produced by Plant A can be represented as 'x-5000'.

Now, 5% of the panels from Plant A and 3% of the panels from Plant B were defective. The total number of defective panels produced by both plants is given as 1190. Therefore, we can write the equation:

0.05(x-5000) + 0.03x = 1190

Simplifying the equation, we get:

0.05x - 250 + 0.03x = 1190

0.08x - 250 = 1190

0.08x = 1440

x = 18000

Therefore, Plant B produced 18000 panels.

Answer 2

Answer: 11,750

Step-by-step explanation:

Given

Plant A produces 5000 fewer panels than B

Suppose B produces x panels

`\therefore A` produces x-5000 panels

A produces 5% defective that is

`\Rightarrow d_a=(x-5000)* 0.05`

B produces 3% defective that is ,

`\Rightarrow d_b=x* 0.03`

Total defective panels is 1190

`\Rightarrow 1190=(x-5000)* 0.05+0.03x\\\Rightarrow 1190=0.08x+250\\\Rightarrow 940=0.08x\\\Rightarrow x=11,750`

So, B produces 11,750 panels.