3.4k views
1 vote
Which of the following ordered pairs (x,y) satisfies both the inequalities y ≥ 3x +8 and y < x?

E. (2,1)
F. (2,-1)
G. (8,-1)
H. (-8,-9

2 Answers

4 votes
The answer would be H -8 -9
User Ezequias Dinella
by
8.9k points
5 votes

Answer:

H. (-8,-9)

Explanation:

Our inequalities:

y ≥ 3x + 8

y < x

To find which ordered pair satisfies both inequalities, we have to plug in values for x and y.

Option E:

y ≥ 3x + 8
y < x

(1) ≥ 3(2) + 8
=1 ≥ 14
(1) < (2)

As we can see, the first inequality is a false statement. So option E is incorrect.

Option F:

y ≥ 3x + 8
y < x

(-1) ≥ 3(2) + 8
=-1 ≥ 14
(-1) < (2)

The first inequality is also a false statement, so this option is also incorrect.

Option G:

y ≥ 3x + 8
y < x

(-1) ≥ 3(8) + 8
-1 ≥ 32
-1 < 8

The first inequality is a false one, so option G is incorrect.

Option H:

y ≥ 3x + 8
y < x

-9 ≥ 3(-8) + 8
-9 ≥ -16
-9 < -8

The first inequality and second inequality are both true. This makes option H the correct one.

Hope this helps! :)

User Spawnia
by
8.5k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories