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An electron in a hydrogen atom has orbital quantum number l= 4. how many possible values of magnetic quantum number ml would it have?

A) 3
B) 4
C) 5
D) 9
E) 10

2 Answers

2 votes

Final answer:

For an electron in a hydrogen atom with an orbital quantum number of l = 4, there are 9 possible values for the magnetic quantum number, ranging from -4 to +4.

Step-by-step explanation:

An electron in a hydrogen atom with an orbital quantum number l = 4 can have multiple possible values for the magnetic quantum number ml.

According to quantum theory, the number of possible values of ml is determined by the formula (2l + 1). Therefore, for l = 4, there would be 2(4) + 1 = 9 possible values for the magnetic quantum number ranging from -4 to 4 inclusive.

This is the reason why the correct answer to the question is (D) 9 possible values for ml.

User Ramanan
by
8.7k points
3 votes

Final answer:

The electron in a hydrogen atom with orbital quantum number l = 4 would have 9 possible values of magnetic quantum number ml.

Step-by-step explanation:

The magnetic quantum number (ml) describes the orientation of the electron's orbit in three-dimensional space. For a given orbital quantum number (l), there can be (2l + 1) possible values for ml. In this case, since l = 4, the possible values of ml would be (2(4) + 1) = 9. Therefore, the correct answer is D) 9.

User IgnisFatuus
by
8.7k points

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