Answer:
0.05 mg/mL ( B )
Step-by-step explanation:
Given data:
20 mg/ml starch
2% solution = 2g of solute is in 100g of solvent
Determine the new concentration in mg/ml
Dilution equation = C1V1 = C2V2
new concentration ; applying the dilution factor
dilution factor = 1 : 400 ; ( 2 /400 )g = 0.005 g of solute is present in every 100 mL
∴ new concentration = 0.00005 g / 1 mL * ( 1000 mg / 1g ) = 0.05 mg/mL