Question

The trapezoid KLMN has the coordinate K (-20, 20) L (-11, 20) M (13, -4) and N (10, -10) what is the perimeter?

1)84.29
2)92.08
3)93.64
3)94.31​

Answer 1

Answer: 2) 92.08

Explanation:

To find the perimeter, you need to use the distance formula which is
`d=\sqrt{(x_(2)-x_(1))^(2)+(y_(2)-y_(1))^(2)}`.

To do this, you take 2 points, let's start with point M and point N. We have (13,-4) and (10,-10). Now, we have
`d=\sqrt{(10-13)^(2)+(-10+4)^(2)`. From there, we get
`d=\sqrt{(-3)^(2)+(-6)^(2)` by doing addition and subtraction. After, we square both to get
`d=\sqrt{9+36` which is
`√(45)` which in decimal form is 6.7082039325 or 6.71 rounded to the nearest hundredth.

Just like that, we can calculate the distance between the other 3 lines. Between points L and M, it's 33.94, between points L and K, it's 9,

and between points K and N, it's 42.43.

Now to find the perimeter, we add all those values up, and get 92.08 as our answer.

Hope that helped a lot.

:)