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What value of x is in the solution set of the inequality 9(2x + 1) < 9x – 18?

–4
–3
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–1

2 Answers

2 votes

Hello!

Answer:


\Large \boxed{\sf x < -3}

Explanation:

We want to solve:


\sf 9(2x + 1) < 9x - 18

Simplify both sides:


\sf 18x + 9 < 9x - 18

Subract 9 from both sides:


\sf 18x + 9-9 < 9x - 18-9

Simplify both sides:


\sf 18x < 9x -27

Subract 9x from both sides:


\sf 18x -9x < 9x -27-9x

Simplify both sides:


\sf 9x < -27

Divide both sides by 9:


\sf (9x)/(9) < (-27)/(9)

Simplify both sides:


\boxed{\sf x < -3}

User Tbaranes
by
7.8k points
4 votes

Final Answer:

x < -3

In-depth explanation:

Hi! This question is asking us to solve this inequality.


\tt{9(2x + 1) < 9x - 18}

Use the distributive property:


\tt{18x+9 < 9x-18}

Subtract 9x from each side:


\tt{18x-9x+9 < -18}


\tt{9x+9 < -18}

Subtract 9 from each side:


\tt{9x < -27}

Finally, divide each side by 9.


\implies\boxed{\tt{\pink{x < -3}}}

User Arminvanbuuren
by
8.3k points

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