117k views
0 votes
Solve for ∠R, to the nearest degree

Solve for ∠R, to the nearest degree-example-1
User Virtuexru
by
8.2k points

2 Answers

5 votes

Answer:


\angle R \approx 58^(\circ)

Explanation:

The Law of Cosines states that for any triangle ABC, where A, B, and C are angles and a, b, and c are sides:
c^2 = a^2 + b^2 -2ab\cos C.

Since we wish to find R, we can use the law of cosines:


8^2 = 7^2 + 9^2 - 2\cdot7\cdot9\cos R

Solving for cos R, we find it to be 11/21. Taking the inverse cosine of this value, we find angle R to have a measure of 58.411864° ≈ 58°.

User HKTonyLee
by
8.8k points
5 votes

Answer:

∠R= 58.4°

Explanation:

For this question, we have to use cosine law. Cosine law is used when there is 3 known side and one unknown angle and there is 1 known angle, two known sides and one unknown side. Memorize the cosine law for unknown angle formula for the unknown angle:

x=
Cos^(-1)(
(a^(2)+b^(2)-c^(2) )/(2ab)) (I'll attach it also)

Here x is the unknown angle and in the attachment it is gamma. a and b can be any of the adjacent sides to x. c is the opposite side of x.

Now plug in the values:

x= Cos^{-1}((9²+7²-8²)/2(9×7))

x= 58.41186°= 58.4°

Solve for ∠R, to the nearest degree-example-1
User Bridal
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories