37.6k views
2 votes
Evaluate ∫⁶⁷₂₆ ∫⁴⁹₀ ∫⁴⁹ᵧ xcos z/z dzdydx.

User Miszmaniac
by
7.8k points

2 Answers

4 votes

Answer:

Explanation:

First, we integrate with respect to z. The integral becomes:

∫⁶⁷₂₆ ∫⁴⁹₀ [xsin(z)]₍ᴢ=⁴₉ᵧ₎₌ₓsin(ᵧ)/ᵧ dydx

Next, we integrate with respect to y. The integral becomes:

∫⁶⁷₂₆ [(xsin(⁴₉ᵧ))-(xsin(⁶₇ᵧ))] / ᵧ dx

Finally, we integrate with respect to x. The integral becomes:

[-cos(⁴₉₀) + cos(⁶₇₂₆)] / ᵧ

User Shashi Shankar
by
7.8k points
0 votes

Answer:

To evaluate the given triple integral, we'll start by integrating with respect to z, then y, and finally x. Let's break down each step:

Step 1: Integrate with respect to z

The integral ∫ xcos(z)/z dz can be evaluated using the basic integral rules. The antiderivative of xcos(z)/z with respect to z is x*sin(z). Therefore, integrating the expression with respect to z gives:

∫ xcos(z)/z dz = x*sin(z)

Step 2: Integrate with respect to y

Now, we need to integrate the expression from Step 1 with respect to y. Since there are no y terms in the integrand, the integral of x*sin(z) with respect to y is simply:

∫ x*sin(z) dy = x*sin(z) * y

Step 3: Integrate with respect to x

Finally, we integrate the expression from Step 2 with respect to x. Since the limits of integration are given as ∫₆₇₂₆ for x, we can evaluate the integral as follows:

∫₆₇₂₆ (x*sin(z) * y) dx

Integrating x*sin(z) * y with respect to x gives us:

= (1/2) * x² * sin(z) * y

Now, we can substitute the limits of integration for x, which are 6 and 7:

= (1/2) * [7² * sin(z) * y - 6² * sin(z) * y]

Simplifying further, we get:

= (1/2) * (49 - 36) * sin(z) * y

= (1/2) * 13 * sin(z) * y

Since there are no more variables to integrate with respect to, this is the final answer for the given triple integral:

∫⁶⁷₂₆ ∫⁴⁹₀ ∫⁴⁹ᵧ xcos(z)/z dzdydx = (1/2) * 13 * sin(z) * y

Note: The value of ∫⁴⁹₀ indicates that the limits of integration for y are from 0 to 49, and the value of ∫⁴⁹ᵧ indicates that the limits of integration for z are from 0 to 49. These values are used in the calculation of the integral.

User Horkavlna
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories