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Which is the standard equation of the circle with center (6,-1) and radius 7

User Ambrosia
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7.2k points

2 Answers

5 votes

Explanation:

we know the equation of circle,

(x - h)² + (y -k)² = r²

Given,

centre(h,k) = (6,-1)

r = 7

Then,from question,

(x - 6)² + (y- (-1))² = 7²

Which is the standard equation of the circle with center (6,-1) and radius 7-example-1
User Lyle
by
8.5k points
4 votes

Answer:


(x -6)^(2) +
(y + 1)^(2) = 49

Explanation:


(x - h)^(2) +
(y - k)^(2) =
r^(2) From the point, (h = 6 and k = -1) and r = 7


(x - 6)^(2) +
(y - -1)^(2) =
7^(2)


(x - 6)^(2) +
(y + 1)^(2) = 49

Helping in the name of Jesus.

User Prashant Sharma
by
7.8k points

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