Question

Which is the standard equation of the circle with center (6,-1) and radius 7

Answer 1

Explanation:

we know the equation of circle,

(x - h)² + (y -k)² = r²

Given,

centre(h,k) = (6,-1)

r = 7

Then,from question,

(x - 6)² + (y- (-1))² = 7²

Answer 2

`(x -6)^(2)` +
`(y + 1)^(2)` = 49

Explanation:

`(x - h)^(2)` +
`(y - k)^(2)` =
`r^(2)` From the point, (h = 6 and k = -1) and r = 7

`(x - 6)^(2)` +
`(y - -1)^(2)` =
`7^(2)`

`(x - 6)^(2)` +
`(y + 1)^(2)` = 49

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