67.2k views
3 votes
The perimeter of the rectangle below is 88 units. Find the length of side WX.

Write your answer without variables.
4
V
4x
X
3x + 2
W

The perimeter of the rectangle below is 88 units. Find the length of side WX. Write-example-1
User Plspl
by
8.4k points

1 Answer

7 votes

Answer:

20 units

Explanation:

L = Length of rectangle = Side VW

= Side YX

=
4x units

W = Width of rectangle = Side WX

= Side VY

=
(3x + 2) units

Perimeter of rectangle = 88 units

Perimeter of rectangle = Sum of exterior sides

=
2(L + W) units


88 = 2[(4x) + (3x + 2)]


88 = 2[4x + 3x + 2]


88 = 2[7x + 2]


88 = 14x + 4


88 - 4 = 14x


14x = 84


x = (84)/(14)


x = 6

Substituting the calculated value of ‘x’ in the expression for the width of the rectangle:

Length of Side WX =
[3(6) + 2] units

=
(18 + 2) units

= 20 units

User Joe McMahon
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories