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The perimeter of the rectangle below is 88 units. Find the length of side WX.

Write your answer without variables.
4
V
4x
X
3x + 2
W

The perimeter of the rectangle below is 88 units. Find the length of side WX. Write-example-1
User Plspl
by
8.4k points

1 Answer

7 votes

Answer:

20 units

Explanation:

L = Length of rectangle = Side VW

= Side YX

=
4x units

W = Width of rectangle = Side WX

= Side VY

=
(3x + 2) units

Perimeter of rectangle = 88 units

Perimeter of rectangle = Sum of exterior sides

=
2(L + W) units


88 = 2[(4x) + (3x + 2)]


88 = 2[4x + 3x + 2]


88 = 2[7x + 2]


88 = 14x + 4


88 - 4 = 14x


14x = 84


x = (84)/(14)


x = 6

Substituting the calculated value of ‘x’ in the expression for the width of the rectangle:

Length of Side WX =
[3(6) + 2] units

=
(18 + 2) units

= 20 units

User Joe McMahon
by
8.0k points

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