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If the derivative of y = x² +2xh is 4, what is the value of h at x= -1.​

User Rik Poggi
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1 Answer

1 vote

Answer:

h=3

Explanation:

To find the value of h at x = -1, we need to differentiate the function y = x^2 + 2xh with respect to x and equate it to 4. Let's start by taking the derivative:

dy/dx = d/dx (x^2 + 2xh)

Using the power rule of differentiation, we get:

dy/dx = 2x + 2h

Now, we know that the derivative is given as 4, so we can set it equal to 4 and solve for h:

2x + 2h = 4

Since we want to find h at x = -1, we substitute -1 for x:

2(-1) + 2h = 4

Simplifying the equation:

-2 + 2h = 4

Now, let's isolate h by moving -2 to the other side:

2h = 4 + 2

2h = 6

Dividing both sides by 2:

h = 6/2

h = 3

Therefore, when x = -1, the value of h is 3.

User Kevinius
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