37.1k views
5 votes
A particle travels along the x-axis such that its velocity is given by v(t) = (t^0.7 + 4t) cos (t^2). What is the average acceleration of the particle on the interval 0thousandth.

User PAULDAWG
by
8.3k points

1 Answer

11 votes

It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.

The average acceleration of the particle over this interval is given by the average rate of change of v(t),


a_(\rm ave) = (v(b) - v(a))/(b - a) = \boxed{((b^(0.7)+4b)\cos(b^2) - (a^(0.7)+4a)\cos(a^2))/(b - a)}

User Justin Lee
by
8.1k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories