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A particle travels along the x-axis such that its velocity is given by v(t) = (t^0.7 + 4t) cos (t^2). What is the average acceleration of the particle on the interval 0thousandth.

User PAULDAWG
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1 Answer

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It's not clear to me what the given interval is supposed to be, so I'll use a generic one, [a, b] with a < b.

The average acceleration of the particle over this interval is given by the average rate of change of v(t),


a_(\rm ave) = (v(b) - v(a))/(b - a) = \boxed{((b^(0.7)+4b)\cos(b^2) - (a^(0.7)+4a)\cos(a^2))/(b - a)}

User Justin Lee
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